Yes. thanks :)

On Fri, May 18, 2012 at 7:06 AM, Jeff Squyres <jsquyres@cisco.com> wrote:
MPI 2 does not say anything about memory sharing.

In Open MPI, each MPI process (i.e., each unique rank in MPI_COMM_WORLD) will have a completely separate memory space.  So the malloc() that you do in MCW rank 0 will be totally different than the malloc() that you do in MCW rank 1.

Make sense?

On May 16, 2012, at 8:08 AM, Rohan Deshpande wrote:

> I have following structure of  MPI code -
>
> int main(){
>
> MPI_INIT.....
> //initialize MPI
> data = malloc(sizeof(int)*200);
>     //initialize data
>    /*--------Master---------*/
>   if(taskid == 0){
>
>     //send data to each slave
>     MPI_SEND....
>    }
>
>    /*----Slaves-------*/
>   if(taskid > 0){
>
>    //accept data from master
>   MPI_RECV....
>   //do some calculations
>  }
>
>  MPI_Finalize()
> }
>
> I have few doubts about the code above.
> In above code, the data is allocated memory in the main program. If I run this program on cluster where
> node 1 is slave and node 0 is master, does node 1 actually shares the memory location of node 0 to perform the calculations?
>
> If I do not want to share the memory, how can i make task on node 1 work independently ?
>
> Thanks in advance.
>
>
>
>
> _______________________________________________
> users mailing list
> users@open-mpi.org
> http://www.open-mpi.org/mailman/listinfo.cgi/users


--
Jeff Squyres
jsquyres@cisco.com
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Best Regards,

ROHAN DESHPANDE