Hello,

I have three processes that communicate with each other. The first process creates the other two processes (using MPI_Comm_spaw (...)).
When one of the processes performs MPI_Finalize (), it continues in execution, stopped in MPI_Finalize function () (in busy waiting, ie, using CPU) and just executes the next instruction only when the other two processes run MPI_Finalize (). It seems that MPI_Finalize () behaves like MPI_Barrier (). This behavior only occurs when processes communicate with each other (when, for example, use MPI_Send,  MPI_Isend, MPI_Bsend. or MPI_Ssend).
I would like to know if we can avoid this behavior of MPI_Finalize when processes communicate with each other.

Here there are the codes:

Process Master:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <mpi.h>

int main(int argc, char** argv) {
    int i;
    char other[200];
    getcwd(other, 199);
    strcat(other, "/otherProcess");
    MPI_Init(&argc, &argv);
    MPI_Comm com;
    MPI_Status s;   
    MPI_Comm_spawn(other, MPI_ARGV_NULL, 2, MPI_INFO_NULL, 0, MPI_COMM_WORLD, &com, MPI_ERRCODES_IGNORE);
    MPI_Recv(&i, 1, MPI_INT, 0, 0, com, &s);
    sleep(15); // Make the otherProcess wait the Master process in MPI_Finalize().
    MPI_Finalize();
    return 0;
}

Other Process (process Master calls otherProcess):

#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>

int main(int argc, char * argv[]) {
    int dest;
    MPI_Comm parent;
    MPI_Init(&argc, &argv);
    MPI_Comm_get_parent(&parent);
    MPI_Send(&dest, 1, MPI_INT, 0, 0, parent); // If this line is removed, the process doesn't stop in MPI_Finalize.
    printf("Before MPI_Finalize\n");
    MPI_Finalize();  // The process stay here waiting all process execute MPI_Finalize.
    printf("After MPI_Finalize\n");
    return 0;
}

I've tried several things but nothing worked. I don't want that otherProcess stay waiting in MPI_Finalize().
Could someone help-me?

Thanks.