On Mon, Dec 13, 2010 at 9:25 AM, Kechagias Apostolos
<pasxal.antix@gmail.com> wrote:
I thought that every process will receive the data as is.Thanks that solved my problem.
2010/12/13 Gus Correa
<gus@ldeo.columbia.edu>
Kechagias Apostolos wrote:
I have the code that is in the attachment.
Can anybody explain how to use scatter function?
It seems that this way im using it doesnt do the job.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <mpi.h>
int main(int argc, char *argv[])
{
int error_code, err, rank, size, N, i, N1, start, end;
float W, pi=0, sum=0;
MPI_Init(&argc, &argv);
MPI_Comm_rank( MPI_COMM_WORLD, &rank);
MPI_Comm_size( MPI_COMM_WORLD, &size);
N=atoi(argv[1]);
int n[N],data[N];
N1 = N/size;
W=1.0/N;
//printf("N1:%d W:%f\n",N1,W);
if(size<2)
{
printf("You must have 2 or more ranks to complete this action\n");
MPI_Abort(MPI_COMM_WORLD,err);
}
if(argc<2)
{
printf("Not enough arguments given\n");
MPI_Abort(MPI_COMM_WORLD,err);
}
if(rank == 0) {for(i=0;i<N;i++) n[i]=i;}
MPI_Scatter (n, N1, MPI_INT,data, N1,MPI_INT, 0, MPI_COMM_WORLD);
pi = 0;
start = rank*N1;
end = (rank+1)*N1;
for(i=data[start];i<data[end];i++) pi+=4*W/(1+(i+0.5)*(i+0.5)*W*W);
// printf("rank:%d tmppi:%f\n",rank,pi);
printf("data[start]:%d data[end]:%d ",data[start],data[end]);
printf("rankN1:%d rank+1N1:%d\n",start,end);
MPI_Reduce(&pi, &sum, 1, MPI_FLOAT, MPI_SUM, 0, MPI_COMM_WORLD);
if (rank == 0) printf("Pi is:%f size:%d\n",sum,size);
MPI_Finalize();
}
#########
Hi Kechagias
If you use MPI_Scatter, the receive buffers start receiving
at the zero offset (i.e. at data[0]), not at data[start].
Also, your receive buffers could have size N1, not N.
I guess the MPI_Scatter call is right.
The subsequent code needs to change.
The loop should go from data[0] to data[N1-1].
(However, be careful with edge cases where the number
of processes doesn't divide N evenly.)
Alternatively you could use MPI_Alltoallw to scatter the way
your code suggests you want to do, but that would be an overkill.
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