Hi Jack,
Debugging OpenMPI with traditional debuggers is a pain.
>From your error message it sounds that you have some memory allocation problem. Do you use dynamic memory allocation (allocate and then free)?
I use display (printf()) command with MPIrank command. It tells me which thread is giving segmentation fault.
Cheers,
Asad
thanksI am not familiar with OpenMPI.Would you please help me with how to ask openMPI to show where the fault occurs ?GNU debuger ?Any help is appreciated.thanks!!!JackJune 30 2010
Date: Wed, 30 Jun 2010 16:13:09 -0400
From: amjad11@gmail.com
To: users@open-mpi.org
Subject: Re: [OMPI users] Open MPI, Segmentation fault
Based on my experiences, I would FULLY endorse (100% agree with) David Zhang.
It is usually a coding or typo mistake.
At first, Ensure that array sizes and dimension are correct.
I experience that if openmpi is compiled with gnu compilers (not with Intel) then it also point outs the subroutine exactly in which the fault occur. have a try.
best,
AA
On Wed, Jun 30, 2010 at 12:43 PM, David Zhang <solarbikedz@gmail.com> wrote:When I got segmentation faults, it has always been my coding mistakes. Perhaps your code is not robust against number of processes not divisible by 2?On Wed, Jun 30, 2010 at 8:47 AM, Jack Bryan <dtustudy68@hotmail.com> wrote:
Dear All,I am using Open MPI, I got the error:n337:37664] *** Process received signal ***[n337:37664] Signal: Segmentation fault (11)[n337:37664] Signal code: Address not mapped (1)[n337:37664] Failing at address: 0x7fffcfe90000[n337:37664] [ 0] /lib64/libpthread.so.0 [0x3c50e0e4c0][n337:37664] [ 1] /lustre/home/rhascheduler/RhaScheduler-0.4.1.1/mytest/nmn2 [0x414ed7][n337:37664] [ 2] /lib64/libc.so.6(__libc_start_main+0xf4) [0x3c5021d974][n337:37664] [ 3] /lustre/home/rhascheduler/RhaScheduler-0.4.1.1/mytest/nmn2(__gxx_personality_v0+0x1f1) [0x412139][n337:37664] *** End of error message ***After searching answers, it seems that some functions fail.My program can run well for 1,2,10 processors, but fail when the number of tasks cannotbe divided evenly by number of processes.Any help is appreciated.thanksJackJune 30 2010_______________________________________________
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David Zhang
University of California, San Diego
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