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Great! Thanks for the fix.
Tim Mattox wrote:
The fix for this bug is in the 1.2 branch as of r19360, and will be in the
upcoming 1.2.7 release.
On Sun, Aug 17, 2008 at 6:10 PM, George Bosilca <email@example.com> wrote:
Thanks for your report. As you discovered we had a memory leak in the
MPI_Alltoallw. A very small one, but it was there. Basically, we didn't
release two internal arrays of data-types, used to convert from the Fortran
data-types (as supplied by the user) to their C version (as required by the
implementation of the alltoallw function).
The good news is that this should not a problem anymore. Commit 19314 fix
this for the trunk, while commit 19315 fix it for the upcoming 1.3.
Thanks again for your report.
On Aug 7, 2008, at 1:21 AM, Dave Grote wrote:
I've been enhancing my code and have started using the nice routine
alltoallw. The code works fine except that there seems to be a memory leak
in alltoallw. I've eliminated all other possible causes and have reduced the
code down to a bare minimum. I've included fortran source code which
produces the problem. This code just keeps calling alltoallw, but with all
of the send and receive counts set to zero, so it shouldn't be doing
anything. And yet I can watch the memory continue to grow. As a sanity
check, I change the code to call alltoallv instead, and there is no memory
leak. If it helps, I am using OpenMPI on an AMD system running Chaos linux.
I tried the latest nightly build of version 1.3 from Aug 5. I run four
processors on one quad core node so it should be using shared memory
phi = 0.
if (mod(ii,1000000_4) == 0) print*,"loop ",ii,izproc
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