Le 25/09/2011 20:27, Gabriele Fatigati a écrit :

if(tid==0){

set_membind(HWLOCMEMBIND_BIND, node 0)
malloc(array)...

}

if (tid==1){

set_membind(HWLOCMEMBIND_BIND, node 1)

for(i...)

array(i)

}

end parallel region

array is allocated on node 1, not node 0 as I expected So it seems set_membind() of second thread influence in some manner array allocation using first touch.

Why do you call set_membind() here? It's whole point is to change the allocation policy of the current thread. If this thread then first-touches some data, this data will obviously get allocated acocording to set_membind().

If you don't want set_membind() to modify the allocation policy of the current thread, why do you call it?

Brice