Ok,
but i dont' understand how lstopo works. Suppose on the physical die the disposition of my cores non SMT) are like this:
Socket:
______________
| ____ ____ |
| |core | |core | |
| ____ ____ |
| |core | |core | |
| ____ ____ |
| |core | |core | |
| ______________|
lstopo how create the numerations? (sorry for the horrible figure). How the numeration start? It consider physical OS index to list and create cores topology? If yes, maybe Core L#0 and Core L#1 in a single socket are physically near.
2011/8/4 Samuel Thibault
<samuel.thibault@inria.fr>
Gabriele Fatigati, le Thu 04 Aug 2011 15:52:09 +0200, a écrit :
> how the topology gave by lstopo is built? In particolar, how the logical index
> P# are initialized?
P# are not logical indexes, they are physical indexes, as displayed in
/proc/cpuinfo & such.
The logical indexes, L#, displayed when passing the -l option to lstopo,
are numbered simply linearly, after having sorted the PUs according to
topology.
--
Ing. Gabriele Fatigati
HPC specialist
SuperComputing Applications and Innovation Department
Via Magnanelli 6/3, Casalecchio di Reno (BO) Italy
www.cineca.it Tel: +39 051 6171722
g.fatigati [AT]
cineca.it